# Euler Problem 1: Multiples of 3 and 5 : C programming solution

**Problem Statement :**

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

**Solution Approach:**

Being the first problem of the series, its quite a simple one. there are many ways to approach this problem.

Most simplest one isĀ to iterate through all the numbers from 3 to 1000 and check if its divisible by 3 or 5. If they are, just add them to the sum. Read More…